- cross-posted to:
- science@lemmy.ml
- cross-posted to:
- science@lemmy.ml
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“WE APOLOGIZE FOR THE INCONVENIENCE”
I think I feel good about it.
Oh no! I have concert tickets that day…
these estimates are going to change a billions of times and humans are probably not going to be there for the most of it.
All of it, they’re human estimates.
Not fucking soon enough
Just when I was gonna have as much money as bezos
Well, then I’m not paying my mortgage anymore.
Not me, I was only able to get 1033 year amortization on mine.
Damn. I better get my shit in order
Why bother when there is so little time left?
You’re right, let’s just call this one and start fresh with the next.
You guys got extra lives?!?!
Meow!
Damn, just two days from retirement…
THE END IS NIGH!!!
Because the researchers were at it anyway, they also calculated how long it takes for the moon and a human to evaporate via Hawking-like radiation. That’s 10^90 years.
Aw shit, there goes my retirement plans
Do you think you’d be able to save enough to retire by then?
idk, in this economy?
looks like we’ve got 1078 years to figure out time travel
any chance we could move that to next week?
Next week is inconvenient for me as my existential dread has flared up again. Can we try tomorrow?
Please don’t, I haven’t played all the video games yet.
You weren’t going to do that anyway.
You don’t know that!
I think I’m getting close to finishing Outer Wilds. Please hold off until I’ve completed that game. Also Half Life 3.
I’m playing this too, and I’m not sure how close I am to finishing it. It feels like the progress gets slower the longer you play and I don’t have any obvious options open anymore. I guess I have to visit some places again and see if I missed something.
Kinda in the same boat as you. Such a strange game. I’m loving it though.
Please. You have at least 10.1^78 hours unplayed in your Steam account.
For comparison, if you had a deck of 52 playing cards and shuffled them into a random order, then checked a year later to see if they were in the same order as when you opened the box, reshuffled if they weren’t, and repeated another year later, and so on…
We can use the cumulative distribution function of the geometric distribution 1 - (1 - p)k, where p is the per-trial probability and k is the number of trials, to find the chance that you’ll find at least one correctly sorted deck from now until the time in this paper. There’s a… Well, SageMath failed because of the exponent, but Wolfram Alpha tells me, uhhhhh…
Yeaaaaaaaaah, we’re not going anywhere any time soon.
Well, it sure feels like forever.
