The average per year is calculated from that number by roughly multiplying with 10 in Europe. I have looked that up and not multiplied by hours in a year.
right, so that’s most likely optimal placement, with peak efficiency being reached for a little while each day as long as the weather is good. if they lie flat, you can lose as much as 90% of that energy, and that’s still with proper maintenance. flat panels also don’t self-clean, so maintenance would be even higher.
basically, you can probably skip the multiplication altogether.
It’s not the most optimal. It’s for a 20% panel slightly south of England:
However, in Michigan, which receives only 1400 kWh/m2/year,[3] annual energy yield drops to 280 kWh for the same panel. At more northerly European latitudes, yields are significantly lower: 175 kWh annual energy yield in southern England under the same conditions
2 kWp means 2 kilo watt peak. It’s the maximum they can produce and in no way the average.
You are right, I considered that.
The average per year is calculated from that number by roughly multiplying with 10 in Europe. I have looked that up and not multiplied by hours in a year.
is that for angled or horizontal?
I don’t know. I just picked the first number I got.
right, so that’s most likely optimal placement, with peak efficiency being reached for a little while each day as long as the weather is good. if they lie flat, you can lose as much as 90% of that energy, and that’s still with proper maintenance. flat panels also don’t self-clean, so maintenance would be even higher.
basically, you can probably skip the multiplication altogether.
It’s not the most optimal. It’s for a 20% panel slightly south of England:
https://en.m.wikipedia.org/wiki/Solar-cell_efficiency
okay, so revise the numbers.
I have calculated conservatively. The result is the lower bound. With optimal conditions twice the energy could be generated.
it’s not though, because we’ve already shown that it was overstated by a factor of 10.